[prakashreddy]

Can you please help me with this question?

Tartaric acid (H2C4H4O6) is neutralized with 0.100M NaOH. A sample of 3.0 g of tartaric acid reacts with 45 ml of base. How concentrated is the base?

I calculated moles of NaOH by multiplying (45/1000)*0.1=0.0045 moles of NaOH.
I can also calculate moles of tartaric acid = 3 g x (1 mole of tartaric acid/150g)=0.02 moles of acid. I am stuck after this step…not sure if i am on the right track. Can someone please help? thank you so much!!

[Hunter2]

You calculated the moles of the acid. How much moles of NaOH correspond to the acid.
If you have this then you know the amount in 45 ml. Concentration is easy to calculate then.

[Borek]

In general: start with the reaction equation.