OK, so assume ρ = 1. Your assumption of n0 = 55.55 is still fallacious.
The mass of 1L of solution is n1M1 + n0M0 = 1000ρ. But substitute n1 = 1, n0 = 55.55 and ρ = 1 and you'll find the two sides are not equal. That's where you come unstuck.
I don't know where you get that complicated equation for c1/x1. If you know (or think you know) n0, then x1 is simply n1/(n1+n0) = 1/(n0+1)
So let's try again. 1L = 1000 g. What is the mass of 1 mol glucose? So what is the mass of water in 1L? How many moles?