I need to know the enthalpy of combustion (heat of combustion) when 1-Hydroxybenzotriazole is burnt stoichiometrically in air. It turns out that HOBt is explosive when heated to 1600C.
I have been unable to find any enthalpy of combustion information for HOBt and have resorted to using bond enthalpy. Is this okay?
I may have simplified the equation too much but I used:
4C6H5N3O + 39(O2 + 79/21N2) => 10H20 + 24CO2 + 12NO2 + 146 5/7N2
The HOBt comprises 16C-H, 12C-C, 12C=C, 8C-N, 4N-N, 4N-OH and 4N=N bond(s) and the oxygen has 39O=O bonds. The enthalpy for bonds broken I calculate to be 42666kJ/mol. (The minus sign signifies a single bond, the equals sign a double bond.)
The reactants have 20H-O, 48C=O and 24N=O bonds. The enthalpy for bonds formed totals 59780kJ/mol. I have ignored the Nitrogen as it cancels out on both sides of the equation.(I hope this is okay!)
Therefore, the enthalpy of combustion for HOBt is -17114kJ/mol.
You may have already guessed that I'm not a chemist but an engineer and there is a chance that some of this compound could get into an incinerator. I need to work out the allowable mass of HOBt that can be burnt at 0.11bar.
Any help in verifying/correcting my equation/calculation will be appreciated. Current calculations indicate 17grams worth of the stuff.