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Topic: Heat transfer.... (Read 6099 times)
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hannah
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Heat transfer....
«
on:
April 20, 2006, 07:40:13 PM »
Uhh okay if you have different amounts of a solution and mix them how do you find the resulting temperature?
Specifically, if you have 30 g H2O at 40 degrees C and 100 g H2O at 70 degrees, what's the resulting temp??
Thanks...
hannah
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Qazzian
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Re: Heat transfer....
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Reply #1 on:
April 20, 2006, 09:40:51 PM »
For that, since it's the same type of liquid (water) in both, just take a weighted average of the temperatures.
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mike
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Re: Heat transfer....
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Reply #2 on:
April 20, 2006, 10:12:56 PM »
Thermometer
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hannah
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Re: Heat transfer....
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Reply #3 on:
April 20, 2006, 11:13:50 PM »
I sort of thought of that, but what if its two different liquids like water and ethanol if i spelled that right?
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Borek
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Re: Heat transfer....
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Reply #4 on:
April 21, 2006, 02:45:47 AM »
Heat balance.
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ChemBuddy
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xiankai
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Re: Heat transfer....
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Reply #5 on:
April 21, 2006, 07:07:02 AM »
heat loss by a substance = heat gain by another substance, assuming no heat loss to surroundings and 100% efficiency
the formula for heat is q = m c dT
where m is mass, c is the specific heat capacity and dT is the temperature change
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hannah
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Re: Heat transfer....
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Reply #6 on:
April 21, 2006, 08:39:14 AM »
Right but how do you do that with two unknowns? it doesn't give me Q or dT...
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Borek
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Re: Heat transfer....
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Reply #7 on:
April 21, 2006, 08:59:43 AM »
Q gained = Q lost, that takes care about first unknown.
Final temperature of both liquids is identical, that takes care of dT.
«
Last Edit: April 21, 2006, 09:07:19 AM by Borek
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Donaldson Tan
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Re: Heat transfer....
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Reply #8 on:
April 21, 2006, 02:58:45 PM »
Although there is 2 unknown (c and T
final
), c cancels out because both "substances" are actually water and therefore have the same heat capacity.
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Heat transfer....