[light]

the recipe:

0.1 M sodium carbonate buffer, pH 9.6 (Ambros Lab)

8 ml of 0.2M sodium carbonate (Na2CO3) (0.2M = 21.2 g/l)
17 ml of 0.2M sodium bicarbonate (NaHCO3) (0.2M = 16.8 g/l)
25 ml of water

...

i have calculated the pH of this buffer and found that it is not 9.6 but 10.0.
sodium carbonate (Na2CO3): (0.2Mx0.008L)/0.025L=0.064M
sodium bicarbonate (NaHCO3): (0.2Mx0.017L)/0.025L=0.136M

pH=pKa+log[base]/[acid]
pH=10.32+log(0.064/0.136)
pH=10

am i doing it right?

thanks for your input!

[AWK]

sodium carbonate (Na2CO3): (0.2Mx0.008L)/0.025L=0.064M
sodium bicarbonate (NaHCO3): (0.2Mx0.017L)/0.025L=0.136M

The final volume is 50 mL (0.05 L) but this not change your result.

Haselbach equation gives quite approximated results, so all is OK at this approximation.

[light]

thanks alot for your *delete me*