Never heard of metamers before, they didn't have them in my day (Fetch my pipe and slippers!) However, a quick look on the internet gives definitions like this:
"The metamerism arises when different alkyl groups are attached to same functional group. E.g.
1) The following metamers contain the ether functional group. However they differ by the nature of alkyl groups attached to the oxygen atom.
metamerism: diethyl ether, methyl propyl ether and isopropyl methyl ether
2) The metamerism is also possible in amines as shown below.
metamerism: diethyl amine, methyl propyl amine and isopropyl methyl amine" (
http://www.adichemistry.com/organic/basics/isomerism/structural/structural-isomerism.html)
But someone else says (
http://padakshep.org/otp/subjects/chemistry/organic-chemistry/structural-isomerism/)
"Metamerism This form of isomerism is rare and is limited to molecules having a divalent atom like O or S and alkyl groups around it. The main examples come from ethers and thioethers."
But I think most people disagree with that limitation.
Here (
https://www.youtube.com/watch?v=EIctIshOR_8) it says that metamers "have the same structure of the carbon chain", but elsewhere says that e.g. methyl n-propyl ether and methyl isopropyl ether are metamers.
Also says that metamers must have a polyvalent functional group and at least four C atoms (which would rule out all your amines).
It is implied (rather than stated) that they have the same functional group, so that e.g. ethanol and dimethyl ether are not metamers. I would apply that to amines: primary, secondary and tertiary amines are different functional groups, and cannot be metamers of each other (video only admits secondary amines). (But he allows butanamide and N-ethylacetamide, which may be a mistake).
I think propylamine, ethylmethylamine and trimethylamine are functional group isomers, and n- and isopropylamine are chain isomers, None of them are metamers.
In the light of the ambiguities and disagreements, I think metamerism is a pointless and unnecessary concept.