I think that what he means is for example the methanium-ion (CH
5+), which actually
has 5 bonds and is considered a superacid.
So let's consider a hydroxonium-cation (H
3O
+).
To determine the formal charge on the oxygen you can use this formula: [formal charge = valence electrons - lone pair electrons - 1/2 × bonding electrons].
So if you fill in: formal charge = 6 valence electrons - 2 lone pair electrons - 1/2 × 6 bonding electrons = a formal charge of +1
For an ammonium-cation (NH
4+) it works the same way: 5 - 0 - 4 = +1
However, in the case of methanium it doesn't really seem to work like that (as where your confusion probably comes from): 4 valence electrons - 0 lone pair electrons - 1/2 × 10 bonding electrons = -1
What's going on here?
The methanium-cation can be seen as a CH
3+-cation, where the empty p-orbital is coordinated to the bond of a H
2-molecule, via a 3-center-2-electron bond.
Viewed in this way, the molecule still has a +1 charge.