December 28, 2024, 05:47:02 AM
Forum Rules: Read This Before Posting


Topic: Finkelstein reaction  (Read 2556 times)

0 Members and 1 Guest are viewing this topic.

Offline Mizushina Rena

  • New Member
  • **
  • Posts: 7
  • Mole Snacks: +0/-1
  • Gender: Female
Finkelstein reaction
« on: January 24, 2016, 05:56:46 AM »
Hello,

I am not sure if the stereochemistry of the following Finkelstein reaction (Walden inversion) is correct :




Offline sjb

  • Global Moderator
  • Sr. Member
  • ***
  • Posts: 3653
  • Mole Snacks: +222/-42
  • Gender: Male
Re: Finkelstein reaction
« Reply #1 on: January 24, 2016, 07:43:48 AM »
How would you tell? Is either epimer favoured?

Offline Mizushina Rena

  • New Member
  • **
  • Posts: 7
  • Mole Snacks: +0/-1
  • Gender: Female
Re: Finkelstein reaction
« Reply #2 on: January 24, 2016, 09:49:27 AM »
The task was to name the product(s). I think that we have here a finkelstein reaction with the walden inversion. That means we except only the (R)-product.  Because it follows a SN2-mechanism.

Offline BRSM

  • Regular Member
  • ***
  • Posts: 17
  • Mole Snacks: +5/-0
  • Gender: Male
  • Process Chemist. Total Synthesis enthusiast.
    • BRSM
Re: Finkelstein reaction
« Reply #3 on: February 07, 2016, 02:46:13 PM »
That's the probably the product you're expected to give - the reaction is SN2 and therefore goes with inversion.

However, it's important to note that in reality, depending on temperature and reaction time you can get iodide displacing iodide in the product, which is a degenerate transformation EXCEPT for stereochemistry. Thus, you'd probably get mixtures of iodide isomers due to this side reaction. If you do a Finkelstein at a stereogenic bromide, you rarely get total conservation of er/dr for this reason.

Sponsored Links