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Topic: C13 NMR question  (Read 3992 times)

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Offline Mark_Z

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C13 NMR question
« on: March 26, 2016, 01:14:39 PM »
I have a sample of what was claimed to be 1,4-cyclohexanediol as a mixture of cic/trans isomers. There are 5 C13 peaks in the NMR that I did on this compound. The vendor claims that there should be 4 peaks representing the 2 isomers, and the 5th peak is maybe due to acetone. I disagree with the vendor. All the NMR predictive softwares I have used says there should only be 2 peaks.

Any thoughts?

Offline Dan

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Re: C13 NMR question
« Reply #1 on: March 26, 2016, 01:25:43 PM »
Your NMR software probably doesn't predict differences arising from the stereoisomerism.

Each isomer should give 2 peaks.

What are the shifts and the NMR solvent used?
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Offline Mark_Z

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Re: C13 NMR question
« Reply #2 on: March 26, 2016, 01:32:26 PM »
My friend did the NMR for me and didn't tic mark the actual chemical shifts. Near as I can make out the shifts are 31, 33, 37, 66, and 68 ppm. Solvent is DMS-d6

Offline Mark_Z

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Re: C13 NMR question
« Reply #3 on: March 26, 2016, 01:44:51 PM »
Stupid wireless keyboard. Make that solvent DMSO-d6

Offline Mark_Z

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Re: C13 NMR question
« Reply #4 on: March 26, 2016, 03:52:17 PM »
I hate admitting I'm wrong, but I was wrong. Went to http://sdbs.db.aist.go.jp/sdbs/cgi-bin/direct_frame_top.cgi, and looked up the 2 isomers. There should be 4 peaks for a mixture of the isomers, separated by about 2 ppm.

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