[StudentinTN]

Hello, I need some help with a Chemistry problem.

I attempted to solve it, but I keep getting the wrong answer. Here is the problem.

4C3H5N3O9(Nitroglycerin) --------> 6N2 + 12CO2 + 10H20 + O2

What is the maximum amount of O2 in grams that can be obtained from 2.00 x 10^2 grams of Nitroglycerin?

This is what I did.

I converted the nitroglycerin to moles. 2.00 x 10^2/908 grams per mole and got 0.22 moles of nitroglycerin.

Then, I used the Factor-Label Method. 0.22 moles of nitroglycerin x (1 mole of O2/4 moles of nitroglycerin), and I got .055 moles of O2.

I converted .055 moles of O2 into grams like this. .055 moles of O2 = X grams/32 grams per mole.

I got 1.76 grams of O2, but the answer in the back of the book shows 7.05 grams of O2.

What did I do wrong?

[wereworm73]

The molar mass of nitroglycerine is 227 g/mole, not 908.

[StudentinTN]

Thank you!

I multiplied the 4 in and didn't even notice! I got the answer now. Thank you very much!