Hello guys, I need your help on that point :
Imagine I have a redox couple which could be oxydized at 1V then it could be also oxydized at 2V
A --1V --> B --2V --> C
But the resistance of my solution is : 1 Ohm.
The equation of the applied potentiel is : dE= Eanod-Ecathode + RI (ohm law) + Overvoltages (we won't consider overvoltages here).
So know imagine that I have applied a potentiel of 2V. What occurs? Does A gives B then C? Or a part of this two volts goes for the resistance and the B to C can't occurs?
Thank you