November 27, 2024, 05:35:02 AM
Forum Rules: Read This Before Posting


« previous next »
Pages: [1]   Go Down

Topic: Free radical substitution  (Read 1931 times)

0 Members and 1 Guest are viewing this topic.

Offline owlpower

  • Regular Member
  • ***
  • Posts: 43
  • Mole Snacks: +0/-1
Free radical substitution
« on: October 16, 2016, 09:43:11 AM »
http://imgur.com/EU2LahU

Hi, I have trouble deducing the number of isomers.
I think that there are 2 possible isomers because the presence of the Br will lead to another alkene forming. Apparently there is only 1 isomeric alkene present? Why is it so?
« Last Edit: October 16, 2016, 09:57:33 AM by Arkcon »
Logged

Offline mjc123

  • Chemist
  • Sr. Member
  • *
  • Posts: 2071
  • Mole Snacks: +302/-12
Re: Free radical substitution
« Reply #1 on: October 17, 2016, 04:55:44 AM »
Show the mechanisms by which you think these two alkenes can be formed.
Logged

Offline owlpower

  • Regular Member
  • ***
  • Posts: 43
  • Mole Snacks: +0/-1
Re: Free radical substitution
« Reply #2 on: October 20, 2016, 08:09:11 AM »
Hi, here's the mechanism I drew. Here it is : http://imgur.com/5Dc5pw3

I managed to get the same alkene. May I ask why the H atom has to be on the adjacent C atom for elimination reactions though?
Logged

Offline mjc123

  • Chemist
  • Sr. Member
  • *
  • Posts: 2071
  • Mole Snacks: +302/-12
Re: Free radical substitution
« Reply #3 on: October 20, 2016, 08:17:16 AM »
How else do you form a C=C bond?
Logged
Pages: [1]   Go Up
« previous next »
Sponsored Links