A sample of food (1.00 g) was mixed with appropriate amount of water and titrated using silver electrode with 0.0200 M AgNO3. The volume necessary to reach the ending point was 5.0 mL. Calculate the %% of NaCl in the food sample.
I got the final answer of .58% by finding the moles of AgNO3 (5mL/1000 *.02M) then getting the grams of NaCl (1:1 ratio so 1*10^-4/58.44g =.005844g NaCl). % of NaCl is equal to .005844/1g *100 which gets me the answer of .58%.
I feel like this was too simple for an analytical chem class so I'm not sure I did this correct.
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Topic: % of NaCl in a sample? (Read 2787 times)