[Morphic flip]

How would a benzene ring be attached to Rh₃(CO)₉ to create a 3 fold axis of symmetry?
I make each Rh bonding to three (CO)₃ groups have 16 electrons, so the remaining 2 electrons needed must be the attachment of another Rhodium to form a triangular arrangement and the benzene ring.
I can only see it as one bond per Rhodium to the benzene ring, but then the bonding in benzene ring would be uneven
Rhodium is 3d⁸

[Dan]

maybe each Rh co-ordinates to benzene in a n² fashion - as it would to an isolated C=C bond. I'd bet a large amount of money that its fluxional too...