[uncreative]

KMnO4+ HCl --> KCl+ MnCl2 + H2O + Cl2


Can you tell me how to balance this reaction?
I know the half reaction method, But to me it doesn't work here!

[AWK]

https://socratic.org/questions/how-to-balance-an-equation-in-its-molecular-form-eg-kmno4-hcl-gives-kcl-mncl2-h2
http://www.periodni.com/balancing_redox_equations.php?eq=HCl%2BKMnO4%3DKCl%2BMnCl2%2BH2O%2BCl2

[uncreative]

Ok thank you
instead if I want to balance this equation

HNO3 + C2H6O + K2Cr2O7 -->  KNO3 + C2H4O + H2O + Cr(NO3)3

so first thing first

This is what I think, please tell me where I do wrong.

Carbon: n.o. from -2 ( in C2H6O) to -1 ( in C2H4O) so it gets oxidized


Chromium: n.o. from +6 (  in K2Cr2O7) to +3 ( in Cr(NO3)3)  so it gets reduced


Now, I have troubles in writing the 2 half reaction

For example, when I write the half reaction for oxidation, which has carbon, do I have to write the entire formula ( C2H6O) or just carbon or carbon and oxyxen?

[AWK]

http://www.periodni.com/balancing_redox_equations.php
put equation in form
HNO3 + C2H6O + K2Cr2O7 = KNO3 + C2H4O + H2O + Cr(NO3)3
and you will get automatic solution with detailed explanation

[uncreative]

Oh this is awesome man! Thanks a lot