[llevene]

OK I know the title of this sounds crazy but like I am really confused with how a 0th order reactant is possible, because that would mean that there is no effect on rate due to concentration. But, when a solution with an extremely high concentration reacts, wouldn't that mean since it has a higher concentration, the odds of molecules colliding and therefore the reaction rate, should be higher than that the same solution at an extremely low concentration?
 
Thanks in advance sorry if this is a really dumb question any help much appreciated!

[Arkcon]

What if a molecule doesn't have to collide with anything?  Look up an example of a zero-order reaction.

[llevene]

What if a molecule doesn't have to collide with anything?  Look up an example of a zero-order reaction.

aah okay so like, if i understood a video i just watched, basically a zero order reaction can be other things for example something decomposing on a hot surface, but like even in the case, for example, of HI_(g) decomposing on hot gold surface, wouldn't a higher concentration of HI mean that more HI molecules would come in contact with the gold at once, meaning the rate of the decomposition would be much higher than if you had a very low concentration of HI?

[llevene]

ooh wait i think i understand! so like basically as an example, if heat is added to something that causes it to decompose, it doesn't matter what the concentration is because it is not colliding with anything, and so the rate will be constant no matter what? Sorry ignore the post i made before that by the way.

[Borek]

ooh wait i think i understand! so like basically as an example, if heat is added to something that causes it to decompose, it doesn't matter what the concentration is because it is not colliding with anything, and so the rate will be constant no matter what?

Yes. Note that it can be thought of as if the heat was the reactant limiting the reaction speed.

Sorry ignore the post i made before that by the way.

That's a great post - even if you were wrong. It shows you are trying to understand the problem applying what you know. Every scientist does that and they all routinely fail when presented with a new problem. Then they try again, and again, till they got it.

That's what you did, didn't you?