[emerson]

I've already found the K_sp of BaCO₃, but now I'm supposed to "use my experimental value of K_sp to determine the solubility of BaCO₃" I got he equation 0=x²+0.1004-5.9 x 10^-5.  Now my question is, am I supposed to use quadratic formula or is there another way to solve for x, cause I'm having a hard time with this 

[syko sykes]

I got he equation 0=x²+0.1004-5.9 x 10^-5. Now my question is, am I supposed to use quadratic formula or is there another way to solve for x, cause I'm having a hard time with this

i don't think you have the right equation because solving that gives you an imaginary number for x

are you sure the equation is 0 = x² + .1004 - 5.9E-5 ?

[FouRRaW]

I didn't read your question thoroughly but i know of this one thing my teacher show'd us so we don't have to use quadratic forumal. 

If you know that x is a very small number ex.(0.00001) as opposed to the other numbers being about 0.01 or something like that.  Use it too you advantage knowing that x is small, then you can add x + (any number) with ease.  Hope this helps

[Borek]

Please elaborate on the source of your equation and numbers used in it. In no way we can guess "the what of a what".

[FouRRaW]

x²                                    [H₃O⁺] [A^-]
                                                             [HA]
_____________

HA - x
                                                     HA + B = HB + A-