November 30, 2024, 12:33:31 AM
Forum Rules: Read This Before Posting


Topic: Morton Light Salt  (Read 16977 times)

0 Members and 1 Guest are viewing this topic.

konshi

  • Guest
Re: Morton Light Salt
« Reply #15 on: June 04, 2006, 05:37:40 PM »
I'm just confused at how the equation looks so different from the other ones I've had to do. For example, another problem was to write a balanced equation to describe vinegar mixed with baking soda and I got the following:    

_1_ CH3COOH (aq) + _1_ NaHCO3 (s) -->  _1_ H2O (l) + _1_ CO2 (g)

That is the extent of which I must make this current problem go to. Morton Light Salt mixed with water. It seems empty to just have KCl(s) -> KCl(aq) as my balanced equation.

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27865
  • Mole Snacks: +1813/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Morton Light Salt
« Reply #16 on: June 04, 2006, 06:05:00 PM »
I understand that. Thing is - there is no "real" reaction going on during dissolution. There is "just" dissolution.

There is more to it (salt dissociates when dissolved) but if you have not yet learn about ions/dissociation it doesn't make sense to confuse you with additional information. Unless you want/hope so for some extra credit or something.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

konshi

  • Guest
Re: Morton Light Salt
« Reply #17 on: June 04, 2006, 06:08:54 PM »
How would it look if dissolution is included in the equation? I may have learned it and simply forgotten. I want to be sure in what answer I'm going to put down and while I could get points taken for not being complete, I doubt points will be taken for having an extended answer.

Thank you for helping me for so long, by the way ^_^

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27865
  • Mole Snacks: +1813/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Morton Light Salt
« Reply #18 on: June 04, 2006, 06:16:17 PM »
Dissolution is already included (by the (aq) symbol). Next step is dissociation:

KI -> K+ + I-
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

konshi

  • Guest
Re: Morton Light Salt
« Reply #19 on: June 04, 2006, 06:20:40 PM »
Hm.. I don't recognize that. I'll stick with just the dissolution part then. Going back, was

Na(s) -> Na(aq)

right?

Or would that be different?

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27865
  • Mole Snacks: +1813/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Morton Light Salt
« Reply #20 on: June 04, 2006, 06:22:12 PM »
No. It should be not sodium, but sodium chloride (it was my mistake, you remember?).
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

konshi

  • Guest
Re: Morton Light Salt
« Reply #21 on: June 04, 2006, 06:23:35 PM »
Ooohhh! Right, right.

Then

NaCl(s) -> NaCl (aq)

?

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27865
  • Mole Snacks: +1813/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Morton Light Salt
« Reply #22 on: June 04, 2006, 06:28:17 PM »
OK
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

konshi

  • Guest
Re: Morton Light Salt
« Reply #23 on: June 04, 2006, 06:34:13 PM »
Thank you very much!   ;D

Sponsored Links