[Ygamie]

Hi Guys my first post.

So the question is...  Blast furnace.... 3 stages

C + O2 > CO2
CO2 + C > 2CO
3CO + Fe2 O3 > 2Fe + 3CO2

if 12g carbon is used in stage 2 and all CO is used in stage 3, what mass of CO2 is produced in stage 3?


It would be great if someone could show me how to work this out.

Many thanks

{MOD Edit -- new title}

[XeLa.]

Okay, could you show us, based on what you've learnt in class, your first steps for attempting to solve this question. That way we can build off of that.

XeLa

EDIT

[Ygamie]

Mr of C 12
Mr of CO is 28 ---> x 2 = 56


My understanding 12 g of C would make 56g of CO based on that equation


Mr of 3CO= 84
3CO2= 44 x 3= 132

84g of 3CO gives 132g of CO2

Therefore (56 x 132)/ 84 = 88g

I think that is right?

Thank you

[Borek]

88 g of CO₂ looks OK.

[Vidya]

Mr of C 12
Mr of CO is 28 ---> x 2 = 56


My understanding 12 g of C would make 56g of CO based on that equation


Mr of 3CO= 84
3CO2= 44 x 3= 132

84g of 3CO gives 132g of CO2

Therefore (56 x 132)/ 84 = 88g

I think that is right?

Thank you

actually you did simple mole ratio stoichiometry

12 g c ---> moles of C -----> moles of CO -----> g CO

[Borek]

actually you did simple mole ratio stoichiometry

12 g c ---> moles of C -----> moles of CO -----> g CO

That's not what the question is asking.

[Vidya]

yes Borek You are right
it is from
12 g c ---> moles of C -----> moles of CO -----> moles of CO2 ----> g CO2
Thanks for correcting me.