Ok, so if this is a diels alder reaction, the two double bonds will break and form methyl groups on the ring, right? And there will only be one double bond in the ring?
Then, the C=C-N, acting as a dienophile will break it's double bond and attach on the the positions as shown in the attached picture?
I still think I am wrong, but I think I am maybe getting closer?
My other idea is that a bicycloproduct will form.
Let me know if I am on the right track
Thank you!
-Melissa