[beloch]

Hello, sorry for my english, I need help with some chemical task. I'm not really into chemistry because i don't have it in in my High School but i have to solve this task. I tried to solve it by my own and this is my result: 7,6187. I need to calculate the pH of solution. I have these informations:

Solution made of:

230 mg KOH
8.71 ml 0.802 mol/l solution of HCl
3 g m/m% NaOH =3.97

diluted to 618 ml

Please use these M: Na – 22,99; Cl – 35,45; K – 39,1.

Round the result on 2 decimal points.


Thank you for your time and help.

[Borek]

Please read the forum rules.

[beloch]

sorry, I've edited it.

[Corribus]

Borek is pointing out that you have to show your work in order to receive help at Chemical Forums.

[beloch]

I said I am not into chemistry. My friend helped me little bit and result was 7,6187. I don't know much about it. I just want to know how to do it not result. I will be happy with the result but it is not necessery, I need some expressions.

[Borek]

You are mixing strong bases with a strong acid, so they will react. The reaction is called neutralization. Whatever is left after the reaction, will be responsible for the final pH.