Hi there
I am hoping to evaluate the UV absorbing properties of a variety of sunblocks.
I hoped to use the following compounds and equipment
- 120 cm3 Ethanedioic acid solution (8g per litre)
- 3 cm3 Potassium hexacyanoferrate III solution (30g per litre)
- 120 cm3 Iron III nitrate solution (12 g per litre)
- 12 Petri dishes
- Source of UV light (preferably a UV lamp)
- 3 different sun screen samples
- Bottle wrapped in aluminium foil for the combined reagent
- 1 Colorimeter
I originally intended to use the following method:
Preparation
1. Make up the three solutions.
For each test, you need about 20 cm3 to cover the bottom of the petri dish, so for 9 samples (3 for each sunscreen) and 3 controls you will need
120 cm3 of ethanedioic acid solution
3 cm3 of potassium hexacyanoferrate III
120 cm3 of Iron III nitrate solution
2. Add 3 cm3 of the potassium hexacyanoferrate III to the ethanedioic acid solution and transfer to the light-proof bottle.
3. Set up your samples. Put 5 g of sunblock on each lid of the petri dishes – remember to keep three free of it as a control
4. Add 120 cm3 of iron III nitrate solution to the reagent bottle and swirl to mix.
The Experiment
1. Pour about 20 cm3 of the combined reagent into each petri dish, replace the lids and then expose to the light source. Measure and note down the reading of the solution from the colorimeter
2. Within a minute or two, depending on the light, you will see a dark blue colour appearing. The more UV light the dish is exposed to, the darker blue the solution.
3. After a set amount of time, use the colorimeter to measure the change in colour that has occurred.
Repeat experiment at least three times.
Explanation:
Interaction of light with the ethanedioate ions leads to their oxidation and releases carbon dioxide and an electron (equation 4a) which then reduces Fe(III) to Fe (II).
C4 H4 O6 2- + hν = 2CO2 + 2C(OH2) + 2e-
Fe 3+ + e = Fe 2+
The Fe(II) formed combines with CN - present in the solution to form the complex [Fe(CN)6]4- which, in turn, gives the insoluble blue Prussian blue, Fe(III)4[Fe(CN)6]3.
Fe 2+ + 6 CN - = [Fe (CN6)]4-
[Fe (CN6)]4- + 4 Fe 3+ = Fe(III)4[Fe (CN6)]3
Unfortunately my school has informed me that I am not permitted to use potassium hexacyanoferate for health and safety reasons.
Can you please recommend an alternative to hexacyanoferate or an entirely different combined reagent that is photosensitive to UV light and will decompose in a linear fashion that I will be able to measure.
Thanks
Henry