November 24, 2024, 12:37:28 PM
Forum Rules: Read This Before Posting


Topic: Determining oxidation numbers  (Read 4422 times)

0 Members and 1 Guest are viewing this topic.

Offline ericbmd

  • Regular Member
  • ***
  • Posts: 14
  • Mole Snacks: +0/-1
Determining oxidation numbers
« on: June 22, 2006, 09:59:05 AM »
In the following reactions, determine the oxidation number for the elements, write the two half reactions, determine what is being oxidized and reduced then label the oxidizing and reducing agents.

I missed this day of our class and the book is extremely confusing.  I'm not sure what to do..


3CuCl2 + 2Al   >>>>   2AlCl3  +    3Cu


2Ca + O2    >>>>>>    2CaO

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27861
  • Mole Snacks: +1813/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Stewed_ant

  • Regular Member
  • ***
  • Posts: 28
  • Mole Snacks: +8/-4
  • Gender: Female
  • The original Arabian Alchemist (student).
Re: Determining oxidation numbers
« Reply #2 on: June 22, 2006, 11:49:07 AM »
To assign oxidation numbers to things, first you look at how many electrons are involved in bonding, then, you assign the electrons to the more electronegative atom in the bond, this atom will become as -ve as the nbumber of electrons that are assigned to it, and the other one will become as positive as the electrons that it had to give to the electronegative atom.

You do this for the other side of the reaction.

atoms which have gone up an oxidation number (become more positive/ or less negative) have been oxidised.
And atoms that have become more negative (or less positive) have been reduced.

Easy as that  ;)
"Where you just going to use a bunsun burner to heat up the petrol??!!!!?" - Demonstrator

"Umm... no?" -Me . minutes later, "few!"
-------
Happiness is a stable octet!

Sponsored Links