Just thinking it through. Suppose the local atmospheric bench-top pressure is 1 atm = 101,325 Pa and temperature is 20 C.
Then the Antoine equation can approximate the partial pressure of water as
P (Pascals) = A + B/(C + T)
Provided 1 <= T <= 100:
P (Pascals) = 10.196213 + 1730.63/(233.426 + T)
At 20 C I get a low partial pressure for water, just 2330 Pa, scarcely contributing to the 101,325 overall assumed pressure.
*"TO DO" Note - Still have to equate R.H. to the 2330 figure above...
Then the calculation seems to be
Molar ratio (air: vapour) = (101,325-2330):2330 = 42.5 : 1
So, 42.5 parts of air, 1 part of water per 43.5 parts overall
Molar volume of ideal gas = RT/P = 0.0241m3 at 1 Atmosphere.
Molar mass of air = 0.028969 kg/mol --> (0.028969/0.024) = 1.207 kg/m3 at 1 Atmosphere
Molar mass of water = 0.018015 kg/mol --> (0.018015/0.024) = 0.751 kg/m3 at 1 Atmosphere
(1.207*42.5)/43.5 + (0.751*1)/43.5 = 1.197 kg/m3 at 1 Atmosphere
The results I get are reasonable, but even using the "Tetens" equation for saturated vapour pressure, differ significantly from published results.
I'm wondering if the "Clausius–Clapeyron relation" can be used?
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PS: When I add hyperlinks, how do I add a hyperlink without showing the long 'http' address, i.e. as a proper hyperlink?
So the above is at [/url]https://en.wikipedia.org/wiki/Clausius%E2%80%93Clapeyron_relation[/url], but that looks ugly compared with "Clausius–Clapeyron"
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