[HuntertheBean]

Hi everyone! I'm currently doing work to prep for my first Gen Chem 2 lab tomorrow, and I got 4/5 from this homework assignment. I was sure that I was doing this problem correctly...but I was way off. The problem goes as follows:

"The concentration of dye in Solution A is 28.447 M. You have 13 mL of water at your disposal to make the dilutions.
The solution is diluted twice, to make Solutions B and C.
In the first dilution, 4 parts of Solution A is diluted with 12 parts water to make Solution B.
3 parts of Solution B is then diluted with 1 part of water to make Solution C.
What is the concentration of dye in Solution C?"

What I used was M1V1=M2V2...like this

(28.447M)(0.004L) = (M2)(0.016L)
M2 = 7.11175M = concentration of Solution B

then...

(7.11175)(0.003L) = (M3)(0.001L)
M3 = 21.335M = concentration of Solution C

Note: I am assuming each part is exactly 1mL

Can someone help me solve this? I would really appreciate it   

[HuntertheBean]

Hi everyone!

Sorry about this! I actually just figured out my tiny mistake. I forgot to use the entire volume for M3...