[dontforgetme]

Determine the enthalpy of reaction for the conversion of butane, C4H10, to butanol, C4H9OH.

the graphs arent showing up on here but the numbers are H=-2881.9 and H=-2712.9

the answers I could get are

a.   169 kJ/mol
b.   –169 kJ/mol
c.   5594.8 kJ/mol
d.   –5594.8 kJ/mol

 and I am not sure which one because I am doing a course online and It's hard trying to teach yourself.

[chenbeier]

To go from butane to butanole, what kind of process is it? What enthalpy these processes obtain?

[Borek]

the graphs arent showing up on here

They won't till you attach them them to your post as a picture.

but the numbers are H=-2881.9 and H=-2712.9

Sorry, no way we can be sure what you mean. We can do some wild guessing at best.

[Enthalpy]

You can append pictures to your messages by "additional options" > Attach. That would help. I don't see what your H numbers are, clearly not the enthalpies of formation. Bond energies maybe? In any case, don't forget the units: they are not only a part of a physical value, they also help you check if your computations make sense.

I dislike something in your question. "Butane to butanol" is not a reaction. The oxygen atom comes from somewhere: from a molecule that has been broken. This used or released enthalpy too. You have to know what the complete reaction is to determine an enthalpy of reaction.