Hello,
Suppose we have a H2SO4 solution in water. We add NaOH and there's a reaction:
H2SO4 + 2NaOH +H2O -> Na2SO4 + 2H2O.
The question is:
How much (volume)of a 12pH NaOH is needed to completely neutralize 25cm^3 of 0.001M H2SO4 solution?
Edit: From this equation we can see that we need 2 moles of NaOH to neutralize 1 mole of H2SO4. But what further?