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redox in basic medium
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Topic: redox in basic medium (Read 1631 times)
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rafarock077
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redox in basic medium
«
on:
November 16, 2018, 08:18:54 PM »
Hi, im needing some help in redox in basic medium.
i can be wrong but the order to balance the half-reactions first you have to add electrons, then h20 and after oh right? but if both compounds have the same electric charge what shpuld i do? also, when i add oh everything that i balance before is useless because oh isnĀ“t neutral
ty 4 the help
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Borek
Mr. pH
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I am known to be occasionally wrong.
Re: redox in basic medium
«
Reply #1 on:
November 17, 2018, 04:06:20 AM »
You got it reversed, you should use OH
-
/H
2
O to balance atoms and then electrons to balance charge.
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ChemBuddy
chemical calculators - stoichiometry, pH, concentration, buffer preparation,
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rafarock077
Regular Member
Posts: 11
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Re: redox in basic medium
«
Reply #2 on:
November 17, 2018, 02:38:44 PM »
so for example in this case "C3 H8 0 - C3 H6 O" (both C3 H8 0 and C3 H6 O are neutrals) first i add oh then h20 and after electrons right? so it end like this, if im not wrong "2oh + C3 H8 O -- C3H6 O + 2h20 + 2electrons"
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Borek
Mr. pH
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Re: redox in basic medium
«
Reply #3 on:
November 17, 2018, 05:50:51 PM »
Looks OK.
Please pay attention to formatting and correct capitalization, there is really no reason other than laziness to not show the equation as
C
3
H
8
O + 2OH
-
C
3
H
6
O + 2H
2
O + 2e
-
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redox in basic medium