Bacterial digestion is an economical method of sewage treatment. The reaction 5CO2 + 55NH4 + 76O2 ---> C5H7O2N + 54NO2 + 52H2O +109H is an intermediate step in the conversion of nitrogen in organic compouinds into nitrate ions. How much bacterial tissue is produced in a treatment plant for every 1.0 x 10^4 kg of wastewater containing 3.0% NH4 ions by mass? Assume that 95% of the ammonium ions are consumed by the bacteria.
I'm assuming the C
5H
7O
2N is the bacterial tissue.
To work out the answer you can work out the mass of ammonium consumed (10000000 x 0.03 x 0.95) which can be converted to moles of NH
4+ consumed by dividing by the M
r(18.0386).
Now that you know the moles of ammonium consumed you can work out the moles of bacterial tissue by dividing by 55.
To convert that into grams you just have to multiply by the M
r(113.1153).
I got 32493.8g of bacterial tissue as the answer, hope that's right!