the Al2O3 in x grams of the mixture to dissolve. the reaction occurring is
Al2O3 + 2OH- + 3H2O ..2Al(OH)4-
800 cm3 of 2 M HCl(aq) is just sufficient to cause all the oxide in x grams of the mixture to dissolve.
AL2O3 + 6H+ ...2Al3+ + 3H2O
MgO + 2H+ ...Mg2+ + H2O
How many moles of each oxide is present in x grams of the mixture?
Moles of MgO = [Total moles of HCl] – [Moles of HCl used for Al2O3] /2
did not get the right answer....??