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Topic: ??  (Read 5580 times)

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jlamping

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??
« on: September 17, 2004, 03:35:07 PM »
A sample of 26.4g of aluminum yields 260.8g of aluminum bromide.  How many grams of bromide react with 16.4g of aluminum?
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Offline Donaldson Tan

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Re:??
« Reply #1 on: September 18, 2004, 03:45:45 PM »
Quote from: jlamping on September 17, 2004, 03:35:07 PM
A sample of 26.4g of aluminum yields 260.8g of aluminum bromide.  

It's obvious that the 260.8g of aluminium bromide formed contains 26.4g of Aluminum by composition (with reference to Law Of Mass Combination). By deducing the number of moles of Aluminium and Bromine from their respective mass combination, you can deduce the emperical formula of Aluminium Bromide.

Quote from: jlamping on September 17, 2004, 03:35:07 PM
How many grams of bromide react with 16.4g of aluminum?

Once you have derrived the emperial formula of aluminium bromide, you can deduce how many moles of bromine has reacted with the number of moles of aluminium equivalent to 16.4g
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"Say you're in a [chemical] plant and there's a snake on the floor. What are you going to do? Call a consultant? Get a meeting together to talk about which color is the snake? Employees should do one thing: walk over there and you step on the friggin� snake." - Jean-Pierre Garnier, CEO of Glaxosmithkline, June 2006

Demotivator

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Re:??
« Reply #2 on: September 18, 2004, 04:08:49 PM »
It's simpler to just set up a proportions equation:
grams Al (1)/grams Br(1) = grams Al(2)/grams Br(2)
where grams Br(1) = (260.8 -  26.4) g
solve for  grams Br(2)
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