Topic: how about the molecules part? (Read 4792 times)

rosystarr · « **on:** November 13, 2004, 08:25:10 PM »

I understand the balancing part now! Although the rest of the problem is How many ammonia molecules are formed by the reaction of three nitrogen molecules?

How do you work it out after you balance?

Thanks again!

kevins · « **Reply #1 on:** November 13, 2004, 08:45:51 PM »

The following is quote form your last question and answered by Geodome,

"multiply through out by lowest common multiple of the denominators to convert the fractions to integer.

Solution: N2 + 3H2 -> 2NH3 (multiply by 2 through out)"

That is to say in "word equation", one molecule of nitrogen react with 3 molecules of hydrogen to form 2 molecules of ammonia.

ssssss · « **Reply #2 on:** November 14, 2004, 08:44:16 AM »

Quote from: rosystarr on November 13, 2004, 08:25:10 PM

I understand the balancing part now! Although the rest of the problem is How many ammonia molecules are formed by the reaction of three nitrogen molecules?

How do you work it out after you balance?

Thanks again!

if you want to balance the reactions in the most possible decent way.Then stop asking on Forums and Work out by trying with lot of Equations yourself.Then if you got any problem we are here to help.

Topic: how about the molecules part? (Read 4792 times)

rosystarr

how about the molecules part?

kevins

Re:how about the molecules part?

ssssss

Re:how about the molecules part?

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