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Topic: Writing Equations: Help  (Read 16120 times)

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libra78wolf

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Writing Equations: Help
« on: February 28, 2005, 04:13:20 AM »
I have a few ?'s

1. I need to write a molecular equation and NIE
You add 1ml dilute HNO3 with to a few grains of iron fillings. Then add 3ml water and 1ml ammonium thiocyanate. How do I approach this problem and solve. I am confused because it doesn't seem to be a double replacement.

2. Next I attempted to try and balance these two equations but could not

H2C4H4O5+NaOH-->H20+NaC4H4O5

H3C4H4O5+NaOH-->H2O+NaC6H5O7

I have put numbers on both sides of the equation but it never quite balances. Some advice please

My last question is regarding this equation

2NaI+Cl2-->2NaCl+I2
Would the net ionic equation completely cancel out because that is what keeps happening when I do it.

2Na+ +2I-+2Cl--->2Na++2Cl-+2I-
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Offline Borek

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Re:Writing Equations: Help
« Reply #1 on: February 28, 2005, 05:57:02 AM »
Quote from: libra78wolf on February 28, 2005, 04:13:20 AM
I need to write a molecular equation and NIE
You add 1ml dilute HNO3 with to a few grains of iron fillings. Then add 3ml water and 1ml ammonium thiocyanate. How do I approach this problem and solve. I am confused because it doesn't seem to be a double replacement.

You have two different, rather simple reactions - first, Fe reacts with acid. If it was non-oxidizing acid (like HCl) Fe will be oxidized to Fe2+, here the reaction will go a little bit further. Second, Fe3+ reacts with SCN- ions and a complex is created. You should be able to google its characteristics.

Quote
2. Next I attempted to try and balance these two equations but could not

H2C4H4O5+NaOH-->H20+NaC4H4O5

H3C4H4O5+NaOH-->H2O+NaC6H5O7

I have put numbers on both sides of the equation but it never quite balances. Some advice please

Not every reaction can be balanced. These two can't. Are you sure you have entered them correctly?

Quote
My last question is regarding this equation

2NaI+Cl2-->2NaCl+I2
Would the net ionic equation completely cancel out because that is what keeps happening when I do it.

2Na+ +2I-+2Cl--->2Na++2Cl-+2I-

Cl2 is not 2Cl-.
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libra78wolf

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Re:Writing Equations: Help
« Reply #2 on: February 28, 2005, 01:25:49 PM »
When I originally write the molecular equation for

NaI + Cl2--> NaCl + I

do I make the iodine I2 or leave it as I and then balance the equation?
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Offline Borek

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Re:Writing Equations: Help
« Reply #3 on: February 28, 2005, 08:00:40 PM »
Cl2 oxidizes I- to I2, at the same time I- reduces Cl2 to Cl-. Uncharged molecules can be a part of NIE when they are necessary - they are here.
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Offline AWK

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Re:Writing Equations: Help
« Reply #4 on: March 01, 2005, 03:52:47 AM »
Iron reacts with diluted  HNO3 according to reaction
Fe + HNO3 = Fe(NO3)3 + NO + H2O  (unbalanced)

then
Fe3+ + n SCN- = Fe(SCN)n where n can be 1 to 6 and charge at Fe from +2 to -3, respectively


Quote
Not every reaction can be balanced.
Every reaction could be balanced

H2C4H4O5+NaOH-->H20+NaHC4H4O5

Malic acid id a dicarboxylic acid and can also react with 2 molecules of NaOH

H2C4H4O5+2NaOH-->2H20+Na2C4H4O5


Formula
Quote
H3C4H4O5
is incorect.


Correct reaction is:
2Na+ + 2I- + Cl2 ---> 2Na+ + 2Cl-+ I2
« Last Edit: March 01, 2005, 03:55:34 AM by AWK »
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Offline Borek

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Re:Writing Equations: Help
« Reply #5 on: March 01, 2005, 06:19:32 AM »
Quote from: AWK on March 01, 2005, 03:52:47 AM
Every reaction could be balanced

I think you are wrong. I will agree (I can even apologize :) ) when you balance the equation entered by the OP (not the one with his mistake - lacking H in product - corrected):

H2C4H4O5+NaOH-->H20+NaC4H4O5

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