Thanks you guys
Especially with the last reply
To form an acyl anhydride you need to treat a deprotonated carboxylic acid with an acyl chloride. Here you have neither a carboxylic acid nor an acyl chloride; methyl 3-methylbutanoate is an ester. Treating an ester with (aqueous) base results in a saponification reaction. The ester is hydrolyzed to produce methanol and sodium 3-methylbutanoate (which becomes 3-methylbutanoic acid after acid workup).
I ended up finding it the book as well
I got some more questions, if you don't mind looking over them
My questions are:
1. 3-methylbutanoic acid + SOCl
2=
2. 3-methylbutanoic acid + DCc, methanamine=
3. 3-methylbutanoic acid + heat=
4. 3-methylbutanoic acid +methanol acid catalysis=???
5. diethyl heptanediaote + sodium ethoxide + bromoethane + hydrolysi + heat=???
My Answers:
1. 3-methylbutanoyl chloride, because a carboxylic acid with a SOCl
2 and pyridine catalyst make a Acyl halide.
2. N,3-dimethylbutanamide, because carboxylic acid with amine, followed by DCC will results in a amide that's either primary, secondary, or tertiary.
3. 3-methyl butananoic anhydride, because carboxylic acid with heat and assuming an acid cataylst will result in an anhydride.
4. methyl 3-methylbutanoate, because carboxylic acid with an alcohol followed with an acid catalyst will result in an ester alkyl alkanoate.
5. cyclohexanone
, with this one I know that at least I'm going to form a cyclohexanone, but I'm not sure if I keep an ethyl group attached to it.
Are these correct???
Thank You