December 27, 2024, 02:53:56 PM
Forum Rules: Read This Before Posting


« previous next »
Pages: [1]   Go Down

Topic: HCL required?  (Read 14368 times)

0 Members and 3 Guests are viewing this topic.

TJFCDA

  • Guest
HCL required?
« on: August 03, 2005, 12:06:06 PM »
What is the quantity of 32% HCL required to dissolve one (1) pound of CaCO3 (calcium carbonate)?
Logged

Offline sdekivit

  • Chemist
  • Full Member
  • *
  • Posts: 403
  • Mole Snacks: +32/-3
  • Gender: Male
  • B.Sc Biomedical Sciences, Utrecht University
Re:HCL required?
« Reply #1 on: August 03, 2005, 12:10:52 PM »
first this question can't be made if you don't know the density of the HCl-solution.

If you know the density of the HCl-solution, then take, for example, 1L solution. You can calculate the mass of 1L HCl with the density and using the mass% you know the mass of HCl in 1L.

--> convert to mol and you know the molarity of the HCl-solution (why?)

convert the mass of CaCO3 to mols and then you can calculate how many mL HCl-solution you need to dissolve 1 pound CaCO3.
Logged

Offline Donaldson Tan

  • Editor, New Asia Republic
  • Retired Staff
  • Sr. Member
  • *
  • Posts: 3177
  • Mole Snacks: +261/-13
  • Gender: Male
    • New Asia Republic
Re:HCL required?
« Reply #2 on: August 03, 2005, 12:12:45 PM »
convert 1pound of CaCO3 into number of moles

CaCO3 + 2HCl => CaCl2 + H2O + CO2

every mole of CaCO3 requires 2 moles of HCl to react completely

given the concentration of the HCl solution, find the required volume of the solution to react with 1pound of CaCO3.
« Last Edit: August 04, 2005, 04:26:35 AM by geodome »
Logged
"Say you're in a [chemical] plant and there's a snake on the floor. What are you going to do? Call a consultant? Get a meeting together to talk about which color is the snake? Employees should do one thing: walk over there and you step on the friggin� snake." - Jean-Pierre Garnier, CEO of Glaxosmithkline, June 2006

TJFCDA

  • Guest
Re:HCL required?
« Reply #3 on: August 03, 2005, 01:13:21 PM »
I know that 32% HCL has a density of approximately 10 lbs. per gallon and the molarity is 10.17.

The equation indicates that 1 mole of CaCO3 reacts with 2 moles of HCL.  If 1 mole of CaCO3 = 100.0892g and 1 moles of HCL = 36.461g, then it take 72.922g of HCL to dissolve 1 mole of CaCO3.  Is this correct?

Assuming this is correct.  Shouldn't it require 0.729 lbs of HCL to dissolve 1 lb. of CaCO3?
Logged

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27887
  • Mole Snacks: +1816/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re:HCL required?
« Reply #4 on: August 04, 2005, 04:08:43 AM »
Quote from: sdekivit on August 03, 2005, 12:10:52 PM
first this question can't be made if you don't know the density of the HCl-solution.

Can be done - you just have to give the answer in mass units.
Logged
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27887
  • Mole Snacks: +1816/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re:HCL required?
« Reply #5 on: August 04, 2005, 04:14:10 AM »
Quote from: TJFCDA on August 03, 2005, 01:13:21 PM
I know that 32% HCL has a density of approximately 10 lbs. per gallon and the molarity is 10.17.

Doesn't matter.

Quote
The equation indicates that 1 mole of CaCO3 reacts with 2 moles of HCL.  If 1 mole of CaCO3 = 100.0892g and 1 moles of HCL = 36.461g, then it take 72.922g of HCL to dissolve 1 mole of CaCO3.  Is this correct?

Correct.

Quote
Assuming this is correct.  Shouldn't it require 0.729 lbs of HCL to dissolve 1 lb. of CaCO3?

Yes - but that's not the final answer. This is mass of pure HCl and HCl is only 32% of the solution you have to use.
Logged
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline sdekivit

  • Chemist
  • Full Member
  • *
  • Posts: 403
  • Mole Snacks: +32/-3
  • Gender: Male
  • B.Sc Biomedical Sciences, Utrecht University
Re:HCL required?
« Reply #6 on: August 04, 2005, 04:56:16 AM »
Quote from: Borek on August 04, 2005, 04:08:43 AM
Can be done - you just have to give the answer in mass units.

agreed, but when you want to calculate the volume you'll have to know the molarity of the HCl-solution. That's where i was aiming at.
Logged

TJFCDA

  • Guest
Re:HCL required?
« Reply #7 on: August 04, 2005, 10:21:40 AM »
If I'm using 32% HCL:  0.729/.32=2.27 lbs. of 32% HCL.  Is this correct?
Thanks for your assistance.
Troy
Logged

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27887
  • Mole Snacks: +1816/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re:HCL required?
« Reply #8 on: August 04, 2005, 10:41:13 AM »
Quote from: TJFCDA on August 04, 2005, 10:21:40 AM
If I'm using 32% HCL:  0.729/.32=2.27 lbs. of 32% HCL.  Is this correct?

Seems OK.
Logged
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

TJFCDA

  • Guest
Re:HCL required?
« Reply #9 on: August 04, 2005, 10:50:32 AM »
I calculated the amount of HCL using the following method and came up with a slightly different quantity.  Is this correct?

1 lb. of CaCO3 = 453.59 g CaCO3

453.29 g CaCO3/100.09 g per mole CaCO3 = 4.532 moles CaCO3

4.532 moles CaCO3 x (2 moles HCL/1 mole CaCO3) = 9.064 moles HCL

9.064 moles HCL x (1 liter solution/10.17 moles HCL) = 0.89 liters of 32% HCL

@ 10 lbs/gallon for 32% HCL
0.98 liters of 32% HCL = 0.235 gallons or 2.35 lbs of 32% HCL

Which of my calculations is the most accurate?
Logged

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27887
  • Mole Snacks: +1816/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re:HCL required?
« Reply #10 on: August 04, 2005, 11:05:47 AM »
Quote from: TJFCDA on August 04, 2005, 10:50:32 AM
Which of my calculations is the most accurate?

First one, as it uses only sure numbers.

Quote
I know that 32% HCL has a density of approximately 10 lbs. per gallon and the molarity is 10.17

How good is this approximation?

32.0000% HCl solution is 10.1755M and has a density 1.1594 g/mL.

To say the truth, I have no idea what are pound and gallon in metric terms.

I am assuming 0.89/0.98 is a typo.
Logged
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

TJFCDA

  • Guest
Re:HCL required?
« Reply #11 on: August 04, 2005, 11:37:40 AM »
Sorry for the typo.  Thanks for your support! :)
Troy
Logged
Pages: [1]   Go Up
« previous next »
Sponsored Links