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Topic: Isoelectronic  (Read 8868 times)

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rsixtyone

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Isoelectronic
« on: September 25, 2005, 08:51:05 PM »
I know that F-1 and O-2 are isoelectronic with neon (Ne) since they all have a full octet.  My question is that is Al with +3 charge isoelectronic with neon?

thanks.
« Last Edit: September 25, 2005, 08:53:48 PM by rsixtyone »

Offline mike

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Re:Isoelectronic
« Reply #1 on: September 25, 2005, 09:03:19 PM »
Yes
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rsixtyone

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Re:Isoelectronic
« Reply #2 on: September 25, 2005, 09:09:14 PM »
and which element can form a +2 ion and be isoelectronic with strontium? Ba, Zr, Ti, Se?

i know that it needs to have 4 electrons in its outer shell

Offline mike

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Re:Isoelectronic
« Reply #3 on: September 25, 2005, 09:35:54 PM »
hmmm I'm not sure if any of them are:

Sr:  [Kr]5s2

Ba: [Xe]6s2
Zr:  [Kr]4d25s2
Ti:  [Ar]3d24s2
Se: [Ar]3d104s24p4
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rsixtyone

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Re:Isoelectronic
« Reply #4 on: September 25, 2005, 09:49:43 PM »
really? cause I also have choice E. which is none of the above.

Offline mike

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Re:Isoelectronic
« Reply #5 on: September 25, 2005, 09:59:12 PM »
I think that it is E: none of the above, as if you were to remove the outer two electrons of any of the other choices you would not get an isoelectronic configuration.
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Offline jdurg

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Re:Isoelectronic
« Reply #6 on: September 26, 2005, 08:53:18 AM »
I think that it is E: none of the above, as if you were to remove the outer two electrons of any of the other choices you would not get an isoelectronic configuration.

What happens if you remove the two 4d electrons from Zirconium?   ;)  Remember, the energy differences between the 4d and 5s shell aren't that great, and in order to get an ion out of zirconium you'd have two options; remove the fully paired 5s shell electrons, or the unpaired 4d electrons.  I think the 4d electrons would easily come away compared to the 5s electrons, as it would leave you with full shells when all is said and done.
« Last Edit: September 26, 2005, 08:54:45 AM by jdurg »
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Re:Isoelectronic
« Reply #7 on: September 26, 2005, 04:38:35 PM »
so the none is the answer correct bud?

Offline mike

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Re:Isoelectronic
« Reply #8 on: September 26, 2005, 08:43:41 PM »
What happens if you remove the two 4d electrons from Zirconium?   ;)  Remember, the energy differences between the 4d and 5s shell aren't that great, and in order to get an ion out of zirconium you'd have two options; remove the fully paired 5s shell electrons, or the unpaired 4d electrons.  I think the 4d electrons would easily come away compared to the 5s electrons, as it would leave you with full shells when all is said and done.

Yes this sounds reasonable to me jdurg  :)
There is no science without fancy, and no art without facts.

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