a person's blood sugar level is usually around 100mg per 100cm^3. if this level falls below 60mg per 100cm^3, insulin can occur. the density of blood is 1.2g cm^-3
what is the percentage by mass of sugar in the blood
i)when the blood sugar level is normal??
ii)during insulin shock??
what is the molar concentration of sugar C6H12O6, in the blood
i)under normal conditions??
ii)during insulin shock??
Since the density of blood is 1.2 g /cm^3, then the mass of 100 cm^3of blood is
1.2 * 100 = 120 gm
1) So the percentage by mass of sugar in the normal blood level
= ( 100mg /120g ) * 100 %
= ( 1g /120 g) *100 % = 0.833%
2) During insulin shock
the percentage by mass of sugar = (60mg/120g) * 100%
= (0.6 g /120g)*100 % = 0.5%
For molar concentrations, we need molar mass of sugar
Molar mass of C6H12O6 = 6 * 12 + 12 * 1 + 6 * 16 = 180
1) 1 g of sugar = 1/180 = 0.00556 moles
So molar conc = 0.00556 moles / 100cm^3 = 0.00556/ 0.1L = 0.0556 M
2) 0.6 g of sugar = 0.6/180 = 0.003333
So molar cond = 0.003333/ 100 cm^3 = 0.003333/0.1L = 0.03333M during insulin shock.
does it look right now?