Thanks for the help on my molarity question... one more... could you show me how to make a 1 % HCL solution from 12 M HCL.

Clinical MT

Justwonder is true in this case but this is not a general method.
Let's start form beginning:
12 M HCl contains 12 moles = 12x36.461 g (437.53 g) in 1 L
1 % HCl shows density of 1.005 g/mL and in this case it can be rounded to density of water (usually 1.00 g/mL - but this is also approximation).

We need 10 g od pure HCl for 1L (1kg) of diluted solution.

So we need (10/437.61)x1000 mL of concentrated HCl (22.8 mL or 37.18 g) and water up to 1000 mL or 1005 g which is 967.8 g (or mL).

For 1L of 10 % HCl we need 228 mL 12M HCl (density 1.19 g/mL) weighted 371.8 g.
and enough water to 1000 mL or 1050 g (density of 10 % HCL is 1.05 g/mL) - 678,2 g (or mL) of water.