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Topic: what concentration of alcohol that produces intoxication, unconciusness, death  (Read 6588 times)

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biomed77

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a blood alcohol level of 80mg per 100cm^3 is the ligal limit for driving. a blood alcohol level of about 200mg alcohol per 100cm^3 of blood produces intoxication and around 400mg per 100cm^3 produces unconciousness. at a blood level above 500mg per 100cm^3,a person may die. a)what is the molar concentration of alcohol,ethanol(C2H5OH) that produces...i)intoxication? ii)unconciusness? iii)death? b)a pint of beer contains about 16g ethanol and the distribution volume for a 70kg man is 40dm^3. i)how many pints of beer can he drink before he reaches the ligal limit for driving? ii)if untoxicated,how many pints of beer will he have consumed? iii)if unconcious,how many pints of beer will he have consumed?? thanks
   

a)   I) Intoxication:

We have 200 mg alcohol per 100 ml of blood
Which is 0.2 grams per 100 ml of blood

0.2 g (1 mole / 46.069 g)
= 0.00434 moles ethanol per 100 ml blood
to convert this to molarity,
(0.00434 moles x 1000 ml) / 100 ml
= 0.0434 Molar solution
So, 0.0434 Molar solution causes intoxication

ii) Unconsciousness
which is essentially double of the amount caused for intoxication 0.0868 Molar solution
0.4 g (1 mole / 46.069 g)
= 0.00868 moles
(0.00868 moles x 1000 ml) / 100 ml
= 0.0868 Molar solution

iii) Death
0.5 g (1 mole / 46.069 g)
= 0.0108 moles

= (0.0108 moles x 1000 ml) / 100 ml
= 0.108 Molar solution of ethanol can cause death

b)  

16 g (1 mole / 46.069 g)
= 0.347 moles
0.347 moles distributed in 40 liters is 0.008675 Molar solution
i) Legally allowed limit is 0.017 Molar solution
So, 1.96 pints of beer is a legally allowable limit

ii) If he is intoxicated, he must have consumed 5 pints of beer

iii) If he is unconscious, he must have consumed 10 pints of beer

is this whole thing right???i am totally fed up  :(
« Last Edit: January 28, 2006, 02:18:06 PM by Mitch »

Offline Borek

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Re:volumetric analysis calculations
« Reply #1 on: January 28, 2006, 02:28:45 PM »
0.0434
0.0868
0.108

OK. Depending on the precision of calculations last digit in 0.108 can be 9

Now that you know how to calculate these things, check my CASC ;)

For the second part - there is no need to go through molar concentrations. All you have to do is to convert 16g/40L to mg/100mL to know how high blood level gives one beer.

16g/40L = 16000mg/(40*10) = 40 mg/100mL

(40*10 is number of 100mL portions in 40L)

Note that it means that exactly two beers are needed for driving limit, not 1.96 - difference is probably caused by rounding errors.

But your calculations are - in general - OK.
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