Hi All
We are busy testing Glutathione as per BP monograph. I would like to confirm the calculation for the assay as there is no calculation in the monograph.
BP Assay method:
In a ground-glass-stoppered flask, dissolve 0.500 g of the substance to be examined and 2 g of potassium iodide R in 50 mL of water R. Cool the solution in iced water and add 10 mL of hydrochloric acid R1 and 20.0 mL of 0.05 M iodine. Stopper the flask and allow to stand in the dark for 15 min. Titrate with 0.1 M sodium thiosulfate using 1 mL of starch solution R, added towards the end of the titration, as indicator. Carry out a blank titration.
1 mL of 0.05 M iodine is equivalent to 30.73 mg of C10H17N3O6S
Is the calculation for the Assay as follows:
% = (Blank - Titre) x F x 30.73 X 100 x 100
mass of sample (mg) x (100 - % LOD)
Where,
Blank = Volume of titrant of the blank (mL)
Titre = Volume of titrant of the sample (mL)
F = factor of the 0.05 M Iodine
30.73 = equivalence factor
mass of sample = mass of sample weighed off (mg)
%LOD = % Loss on drying
Thanks so much for the assistance.
Mike