[Sis290025]

Listed below is solubility vs. temperature data for an organic compound in water.

Temp.   sol. in 10 mL water
0--------------0.15 g
20------------0.30 g
40------------0.65 g
60------------1.10 g
80------------1.70 g

a)Using the data in the above table, graph the solubility of the compound vs. temperature. Connect the data points with a smooth curve.
I graphed this; it looks like half of a concave up curve.

b)Suppose 0.1 g of this compound is mixed with 1.0 mL of water and heated to 80° C. Would the entire compound dissolves? Explain.
From the graph at 80*C, 1.70g/10 mL = 0.17 g/mL (solubility). At 80*C with this info, 0.1g/1.0 mL = 0.10 g/mL (solubility). The entire compound would dissolve because the graph's solubility is 0.17 g/mL, so 0.10 g/mL is less than the maximum solubility of 0.17 g/mL at 80*C.     

c)The solution prepared in (b) is cooled. At what temperature will crystals of the compound appear?
Crystals will appear at a temperature that is less than 60*C. At 60*C, the solubility is 0.11 g/mL; 0.11 g/mL is less than 0.10 g/mL. The liquid is not saturated enough. From the graph and pinpointing a number, a solubility of 0.10 g/mL is around 58-59*C. The solubility at a temperature must be less than 0.10 g/mL for crystal formation. 

d)Suppose the cooling described in (c) were continued to 0° C. How many grams of the compound would come out of solution?
At 0*C, the solubility is 0.15/10 mL = 0.015 g/mL. 0.1 g was the starting amount of compound. Will it be 0.1 g - 0.015 g = 0.085 g? 

Any help is appreciated.   

[Borek]

Any help is appreciated.

Everything looks correct at first sight But second opinion won't hurt