I'll have to do this mini- experiment:
TiCl
4 in HCl (15%) ,than I add NH
3 in excess
The reaction should be:
NH
3 + HCl ----> NH
4+ + Cl
-NH
3 is in excess.
So in the solution I'll have OH
- (basic pH) ,some NH
3 ,some Cl
- and TiCl
4Now different things I think they may happen:
1) TiCl
4 + 2OH
- ---> [ TiCl
4OH
2 ]
2- ( I think Titanium can do exacohordinated complex)
2)TiCl
4 + 2OH
- ----> Ti(OH)
4 (ligand excanche)
3)Ti(OH)
4 + 2 OH
- ----> Ti(OH)
6 2-
a) Now I check and I found that the 2) happens.... formation of the complex TI(OH)
4 (is a complex??...or a ionic compound??!) and then precipitation
Why the 1) and 2) can't occour-----
b) in a solution of TiCl4 in HCl (15%) I have only TiCl4...or I have also some TI4+ free (complexation equilibrium)
thanks