You need to open the ring with HBr first, then make triflate and somehow transform the formed bromide to boronic acid or stannane. Then ringclose with Pd(0)/CO.
This is a complicated synthesis, it feels backwards.
Hi
I've tried to do the first step:
Is this what have you thought before?
Now If I have understood I need to convert the -Br to a -SnMe3 group
But in order to do then the stille reaction with Pd +CO should the Sn(Me)
3 be bonded to a vinylic/arylic carbon??
Because in all reactions ( with Pd + CO)that I see in my textbook is alwayas bondes to a sp2/sp carbon...
Ps: bit with the ringlcosing I'll get a "5 atom" cycle...not 6?!
Am I missing something?
Thanks