[Gameofketones]

In the 4th question should I approach it quantitatively like 0.1 N oxalic acid means 0.05M oxalic acid. But then I don't have the molarity of KMNO4 to predict the titre value.

[AWK]

But then I don't have the molarity of KMNO4 to predict the titre value.

You are not asked about it.

[Gameofketones]

Is it asking me if I would adjust in an experiment? Or should i predict if 5ml titre value is correct or not?

[AWK]

How do you understand this sentence?

[Gameofketones]

We have not yet done the experiment. This was given as an assignment..since we can't have physical classes. So I'm guessing we can only answer this after we do the experiment..

[AWK]

All the questions for this exercise can be answered without knowing the specific concentration of permanganate. Moreover, for assignment 4 you can calculate the approximate values ​​of the permanganate concentration yourself if somehow it helps you better understand the problem.

[Borek]

http://www.titrations.info/titrant-and-sample-volume

[Gameofketones]

I got the titrant value 5ml doing in this manner..is this anywhere close to being correct?

[AWK]

The greater the volume of the titrant, but not greater than the volume of the burette, the smaller the titration error.

[Gameofketones]

I understand that titrant value must be greater for less errors. I'm confused because in the question they've said take either 10ml or 25ml. Should I calculate the concentration of KMnO4 and work them out separately?  Since 2 moles reacts with 5moles of oxalic acid, i got 0. 0125 moles of oxalic acid reacts with 0.005 moles of KMnO4. From the no. Of moles, I standardized it to 250ml and got 0.02M is this correct?

[AWK]

Usually, a smaller volume is used for pre-titration. So I understand assignment 4 is for 25mL volume. This, therefore, corresponds to a permanganate concentration of 0.1 and 0.02 M respectively.

[Borek]

I'm confused because in the question they've said take either 10ml or 25ml.

Most likely to allow you to choose the volume which produces smaller error.