Hello. I'm reading in my textbook that reversible reactions can be affected by the concentration of both products and reactants. Though I'm having a bit of difficulty understanding this in the context of effervescent tablets that dissolve in:
1. Normal water
2. Carbonated water
Because according to my textbook, the reaction of dissolving the tablet in
carbonated water should take a longer time because the water already has carbon dioxide and the system is already close to equilibrium.
I understand that these tablets contain citric acid (which gives off oxonium ions) and sodium bicarbonate. The reactions go like this:
1- NaHCO3(s)
Na+(aq)+HCO3-(aq)
2- HCO3-(aq)+ H3O+(aq)
H2CO3(aq)+H2O(l)
3- H2CO3(aq)
CO2(g)+H2O(l)
The problem is that I'm trying to come up with an explanation to why it dissolves slower in the carbonated water but the closest thing that I came up with and that I'm not even sure is right is that: In carbonated water, when we open the bottle, the reaction #3 above goes to the right to build carbon dioxide and water, but when the effervescent tablet is added, the reaction #3 above goes slower because there is already carbon dioxide in the carbonated water and the system is close to equilibrium, therefore the effervescent tablet doesn't break up as easily because the reactions in #2 and #3 go to the left instead.
Am I thinking right or am I completely off track?
Thank you for your time!