Comparing the acidity of RSH and ROH, RSH is more acidic. The reasons are that
1. S-H bond is weaker than O-H bond
2. Negative charge on RS- conjugate base can spread out to a larger surface area on S than on O, decreasing the charge density on S than O
What I said was
O > S in terms of electronegativity. Since in both compounds. Since the R group is the same(no change in electrodonating effecf), O would intensify the negative charge on RO- conjugate base more than S on RS-. Thus RSH is more acidic.
This was not accepted because "O or S electron withdrawing effect cannot be considered as it is the group in question"
Why can't I consider its electron withdrawing effect? I do not get it.