[moreche28]

Hello.

I've been struggling to solve the following problem. We have to calculate the depth (in m) to which a balloon full of Kr must be pushed underwater to make it sink to the bottom of the sea. It takes place at 25 degrees Celsius, we know that p (atm) = 101 325 Pa, density (of sea H₂O) = 1.04 g/cm³, g = 9.81 m/s² and the M (Kr) = 83,8 g/mol, and that Kr acts as an ideal gas.

Firstly, I've calculated the density of Kr ( = 3.74 g/dm3), and I know that the p (fluid) = ρ * h * g. Does anyone have any ideas about what to do next?

Thank you!

[Orcio_87]

Density of the Kr must be higher that density of the sea water. The higher pressure the higher density of the gas.

[moreche28]

Thank you. Hopefully, I've managed to solve it using the following equation: p₁*V₁ = p₂*V₂, and therefore: p₁*V₁ = ρ * h * g * (m/ρ) => p₁*V₁ = h * g * m. But how should I calculate the new density?

[Orcio_87]

Density of the Kr must be higher that density of the sea water (1,04 g/ml).

[moreche28]

Yes, I've got this. But I'm not sure the equation is right.

[Orcio_87]

Density is the mass to the volume ratio (higher pressure decreases the volume).