[luscofusco]

In this exercise I have to explain the mechanisms for that transformation.
I understand that the H⁺ protonates the OH and then the molecule loses the H₂O and forms a carbocation, but I'm stuck there.
I know there is a rearrangement but I'm not able to see it. Maybe C1 will bond with C3 somehow? There are no H in C2 for the hydride shift to happen, is it coming from one of the methy on that C2? And after that it would react with water in a elimination reaction to form the double bond. It is just a gess, I know I'm missing something.

[Meter]

You start with a seven-membered ring and end with a six-membered ring. Is there a way your ring can rearrange such that the carbocation is still "moved" to a stable position?

[luscofusco]

I've done this:

C1 bonds with C3 and the carbocation is displaced to C2 and then water takes one of the beta H of one of the methyl groups and forms the double bond. At first I thought I was missing a carbon and had to do it a couple of times. Does this make sense?

[Meter]

I've done this:

C1 bonds with C3 and the carbocation is displaced to C2 and then water takes one of the beta H of one of the methyl groups and forms the double bond. At first I thought I was missing a carbon and had to do it a couple of times. Does this make sense?

Can you draw and show a mechanism? Because it sounds right.

[luscofusco]

Yes, I did this.

[Meter]

Looks about right. Remember to draw your arrows from the bond, not the atom.