Chemical Forums
1 Hour
1 Day
1 Week
1 Month
Forever
December 22, 2024, 08:30:37 AM
Forum Rules
: Read This Before Posting
Home
Help
Search
Login
Register
Chemical Forums
Chemistry Forums for Students
Organic Chemistry Forum
Organic Chemistry Forum for Graduate Students and Professionals
New concentration help with solvent proportion
« previous
next »
Print
Pages: [
1
]
Go Down
Topic: New concentration help with solvent proportion (Read 1803 times)
0 Members and 2 Guests are viewing this topic.
learningworld
Very New Member
Posts: 1
Mole Snacks: +0/-0
New concentration help with solvent proportion
«
on:
November 12, 2021, 07:51:13 PM »
Could you help with this one please? I’m stuck!
From a stock of 20% resin diluted in a mix of 2 solvents (5:1) I have lowered the concentration to 15% by adding 10ml of a different solvent onto 40ml of the initial stock. Which proportion do I have of these 3 solvents now?? And could you let me know how do I calculate this for future work please? Many thanks
Logged
Orcio_87
Full Member
Posts: 440
Mole Snacks: +39/-3
Re: New concentration help with solvent proportion
«
Reply #1 on:
November 13, 2021, 03:31:13 AM »
How to calculate - 80 % of 40 ml initial stock were the 2 solvents in ratio 5 to 1. Their quantity didn't change after the add 10 ml of third solvent, but concentration dropped by 50 / 40. Third solvent occupies 10 of 50 ml total volume.
Logged
Print
Pages: [
1
]
Go Up
« previous
next »
Sponsored Links
Chemical Forums
Chemistry Forums for Students
Organic Chemistry Forum
Organic Chemistry Forum for Graduate Students and Professionals
New concentration help with solvent proportion