November 26, 2024, 06:55:07 AM
Forum Rules: Read This Before Posting


« previous next »
Pages: [1]   Go Down

Topic: Benzene  (Read 1861 times)

0 Members and 1 Guest are viewing this topic.

Offline vernii

  • Regular Member
  • ***
  • Posts: 14
  • Mole Snacks: +0/-0
Benzene
« on: December 16, 2022, 11:19:46 AM »
Explain the reaction between benzene sulphonyl chloride and NaOH.

I am stuck at the point that HCl will release from the reaction i.e NaOH will give H+ but it is a base right? Then how?
Logged

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27864
  • Mole Snacks: +1813/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Benzene
« Reply #1 on: December 16, 2022, 02:42:49 PM »
Quote from: vernii on December 16, 2022, 11:19:46 AM
NaOH will give H+

Please elaborate, apparently you are confusing something - NaOH will consume H+, not produce one.
Logged
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline vernii

  • Regular Member
  • ***
  • Posts: 14
  • Mole Snacks: +0/-0
Re: Benzene
« Reply #2 on: December 17, 2022, 03:49:37 AM »
Try carrying out the reaction between the two molecules.
Logged

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27864
  • Mole Snacks: +1813/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Benzene
« Reply #3 on: December 18, 2022, 03:45:49 AM »
I don't think HCl is a product of this reaction.
Logged
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info
Pages: [1]   Go Up
« previous next »
Sponsored Links